Mass specific metabolic rate (R/M) is then:
The two relationships above are what we saw in (Eckert, Fig. 16-7b). We can look at the relationship between mass-specific metabolic rate and animal mass for a range of mammals - (Eckert, Fig. 16-7a)
and ...
These two relationships are straight lines if we plot log(R) or log(R/M) vs. log(M). (Eckert, Fig. 16-7c) The slopes of these straight lines are b and (b-1), respectively. IMPORTANT - Equation 16-6 on pg. 677 is wrong!
If we are comparing two spherical bodies, l is the radius and surface area = 4 Pi l2 (c = 4 Pi). If we double the radius, the surface area increases by 4 times. If we are comparing two cubes, l is the width and height of each one of the faces of the cube and surface area = 6 l2 (c = 6). If we double the linear dimension of each face, the surface area of each face, and thus of the cube, increases by 4 times.
Volume (V) is proportional to linear dimension (l) in the following way:
If we are comparing two spherical bodies, volume = (4/3) Pi l3 (d = (4/3) Pi). If we double the radius, the volume increases by 8 times. If we are comparing two cubes, volume = l3 (d = 1). If we double the width of one face, the volume increases by 8 times. Mass is also proportional to the cube of linear dimension since if we have more volume and the density of material remains the same, so, M = e l3, where e is just another proportionality constant.
Now, let's take the log of the surface and the mass relationships:
and ...
So, if we plot log of the animal's surface area vs. log of the animal's mass for different animals of different sizes (different l's), as we increase l (the animal becomes longer, higher, and deeper in the same proportion), the log(S) increases by 2 units while at the same time log(M) increases by 3 units. In other words, the slope of the log(S) vs. log(M) relationship is 2/3 or 0.67. This is for an isometric relationship. Only adults of the same species obey this relationship.
When we compare many different species, the log(S) vs. log(M) relationship has a slope of 0.63 instead of 0.67, because of the thickening of bones and other body structures in larger animals (allometric scaling - proportions change as overall size changes). (Eckert, Fig. 16-9)
All text and images, not attributed to others, including course examinations and sample questions, are Copyright, 2009, Thomas J. Herbert and may not be used for any commercial purpose without the express written permission of Thomas J. Herbert.